2025年02月28日

find the file that contains regex

find . -type f -exec sh -c 'strings "$1" | grep -qE "^[A-Za-z0-9]{32}$"' _ {} \;

the challenge was the same as the previous level.

using manpages for find, we get this following:

find / -user bandit7 -group bandit6 -size 33c ! -executable  2>/dev/null

the 2>/dev/null exists to get rid of all Permission denied errors getting printed to the standard output.

interesting challenge, not that difficult.

certainly, i can still use grep to solve this level: cat data.txt | grep millionth.

but it’s quite restrictive if it were applied on another scenario (hinting level 8 here). which is why i tried using sed then pipe it to awk.

i have used this before but never figured them out properly in the past.

simply put, just chain those two together: sed -n '/^millionth\t/p' data.txt | awk '{print $2}'.